What does this error mean? Opening Excel documents with Openpyxl [duplicate]

This question already has an answer here:

• python open() method IOError: [Errno 2] No such file or directory: 2 answers

This error pops up despite having a valid excel file "abc,xlsx" .

>>> import openpyxl
>>> wb = openpyxl.load_workbook("abc.xlsx")

Traceback (most recent call last):`enter code here`
  File "<pyshell#1>", line 1, in <module>
    wb = openpyxl.load_workbook("abc.xlsx")
  File "C:Python27libsite-packagesopenpyxlreaderexcel.py", line 151, in load_workbook
    archive = _validate_archive(filename)
  File "C:Python27libsite-packagesopenpyxlreaderexcel.py", line 115, in _validate_archive
    archive = ZipFile(filename, 'r', ZIP_DEFLATED)
  File "C:Python27libzipfile.py", line 756, in __init__
    self.fp = open(file, modeDict[mode])
IOError: [Errno 2] No such file or directory: 'abc.xlsx'